Explain why fluorine is more reactive than iodine, and describe the trend in boiling points as you go down Group 7.

Edexcel GCSE Chemistry (1CH0) — 6.2 Group 7 · Explain · 4 marks · View as Markdown

Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).

Model answer (4 marks)

Fluorine is more reactive than iodine because its outer shell is much closer to the nucleus, giving it a smaller atomic radius and a higher effective nuclear charge. This makes fluorine a stronger electron‑acceptor; it gains an electron more easily and attracts an incoming electron more strongly than iodine.

Boiling points increase down Group 7. The larger, more polarisable halogen atoms have stronger London dispersion forces, so iodine has a higher boiling point than bromine, which in turn is higher than chlorine and fluorine.

Examiner tips

  • Use the term ‘effective nuclear charge’ or ‘atomic radius’ to justify reactivity. Mention ‘electron‑acceptor’ or ‘gains an electron’. State the trend ‘boiling points increase down the group’. Give the correct order of boiling points: I > Br > Cl > F.

Common mistakes

  • Confusing reactivity with electronegativity without linking to atomic size. Saying ‘fluorine is more reactive because it is lighter’. Giving the wrong order of boiling points (e.g., F > Cl).

Mark scheme (4 marks)

  1. Fluorine is more reactive than iodine because fluorine's outer shell is closer to / smaller atomic radius than iodine's outer shell
  2. So fluorine gains an electron more easily / attracts an incoming electron more strongly than iodine
  3. Boiling points increase going down Group 7
  4. So iodine has a higher boiling point than fluorine / chlorine / bromine (correct relative comparison stated)

Key terms in this question

boiling points · Group 7

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