Explain how the absorption of light by photosystems I and II leads to the reduction of NADP⁺ to NADPH during the light-dependent reactions of photosynthesis.

IB DP Biology Standard Level (2023 syllabus) — C1.3 Photosynthesis · Explain · 4 marks · View as Markdown

Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).

Model answer (4 marks)

Light energy absorbed by pigments in PSII excites electrons to a higher energy level.
These excited electrons travel through the electron transport chain, losing energy that is used to produce ATP by photophosphorylation.
The electrons reach PSI, where a second absorption of light re‑energises them to an even higher energy level.
The re‑energised electrons are then transferred to NADP⁺, reducing it to NADPH with the addition of protons (H⁺).

Examiner tips

  • Use the exact sequence: PSII excitation → electron transport → ATP synthesis → PSI re‑excitation → NADP⁺ reduction.
  • Mention the role of protons in forming NADPH.
  • Keep the answer concise and use the terminology "electron transport chain", "photophosphorylation" and "re‑energised".

Common mistakes

  • Confusing the order of PSII and PSI excitation.
  • Omitting the role of ATP synthesis or proton addition.
  • Using vague terms like "light energy” without specifying the photosystems involved.

Mark scheme (4 marks)

  1. Light energy is absorbed by pigments in photosystem II, causing excitation/boosting of electrons to a higher energy level
  2. Excited electrons from PSII pass along an electron transport chain, losing energy used to produce ATP (by photophosphorylation)
  3. Electrons from the transport chain reach PSI, where light energy is absorbed again, re-energising/boosting the electrons to an even higher energy level
  4. The re-energised electrons from PSI are used to reduce NADP⁺ to NADPH (with the addition of H⁺/protons)

Key terms in this question

NADP⁺ · NADPH

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