Explain how the products of the light-dependent reactions are used in the Calvin cycle to produce triose phosphate (TP).
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
1. CO₂ is fixed by RuBP via rubisco to give 3‑phosphoglycerate (3‑PGA). 2. ATP from the light reactions phosphorylates 3‑PGA to 1‑,3‑bisphosphoglycerate. 3. NADPH donates electrons (hydrogen) to reduce 1‑,3‑bisphosphoglycerate to glyceraldehyde‑3‑phosphate (G3P), a triose phosphate. 4. Some G3P is used to regenerate RuBP (requiring ATP) while the rest exits the cycle to build sugars.
Examiner tips
- Use the exact terms ATP, NADPH, RuBP, rubisco, CO₂, 3‑PGA, G3P; link each to the step it supplies. Show the flow from CO₂ fixation to reduction and regeneration. Mention that ATP is for phosphorylation and NADPH for reduction. Include that some TP leaves the cycle for biosynthesis.
Common mistakes
- Confusing ATP with ADP or omitting the role of NADPH; not stating that RuBP is regenerated; writing that CO₂ is directly reduced to G3P without mentioning rubisco or 3‑PGA.
Mark scheme (4 marks)
- ATP from the light-dependent reactions provides energy for the phosphorylation of glycerate-3-phosphate (G3P) / for the reduction step in the Calvin cycle
- NADPH acts as a reducing agent / donates hydrogen/electrons to reduce G3P to triose phosphate
- Carbon dioxide is first fixed into G3P / RuBP accepts CO₂ to form G3P via rubisco, before ATP and NADPH are used
- Some TP is used to regenerate RuBP (using ATP) so the cycle can continue / some TP leaves the cycle to form organic molecules such as glucose
Key terms in this question
Calvin cycle · triose phosphate (TP)
Related
- All IB DP Biology Standard Level (2023 syllabus) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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