Bromine water decolourises when it reacts with propene. A student investigates how the initial concentration of bromine affects the initial rate of this reaction at constant temperature. When the concentration of bromine is doubled, the initial rate of reaction doubles. Explain what this tells the student about how bromine concentration affects the rate of this reaction, and describe one other factor, besides concentration, that the student would need to keep constant to make the investigation a fair test, explaining why it must be controlled.

AQA A-Level Chemistry (7405) — 3.1.9 Rate equations (A-Level only) · Explain · 5 marks · View as Markdown

Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).

Bromine water decolourises when it reacts with propene. A student investigates how the initial concentration of bromine affects the initial rate of this reaction at constant temperature. When the concentration of bromine is doubled, the initial rate of reaction doubles.

Model answer (5 marks)

The rate is directly proportional to the concentration of bromine, i.e. the reaction is first order with respect to bromine.

When the concentration of bromine is doubled, the number of bromine molecules per unit volume doubles, so the collision frequency between bromine and propene molecules also doubles.

Because the rate of successful collisions is proportional to the collision frequency, the initial rate of reaction doubles.

One other factor that must be kept constant is temperature.

Temperature must be controlled because an increase in temperature raises the kinetic energy of the molecules, increasing the proportion of collisions that have energy equal to or greater than the activation energy, which would otherwise increase the rate and confound the effect of bromine concentration.

Examiner tips

  • Use the word ‘directly proportional’ and state ‘first order’ to gain full marks for the rate law. Show the logical chain: double concentration → double collision frequency → double rate. Name a control variable (temperature) and give a clear reason why it must be constant.
  • Remember to mention the collision theory explanation – students who skip this lose marks.

Mark scheme (5 marks)

  1. The rate is directly proportional to the concentration of bromine / the reaction is first order with respect to bromine
  2. When concentration doubles, the number of bromine particles per unit volume doubles / collision frequency between bromine and propene molecules doubles
  3. This leads to a proportional increase in the rate of successful collisions / rate of reaction
  4. Named control variable: temperature / concentration of propene / surface area (if propene is a liquid or solid form) — one acceptable named variable
  5. Correct explanation of why the named variable must be controlled — e.g. increasing temperature increases the kinetic energy of particles / increases the proportion of particles with energy greater than or equal to the activation energy, which would also increase the rate, making results unreliable; OR changing propene concentration would change collision frequency independently of bromine concentration

Key terms in this question

rate of reaction · concentration

Related

More Rate equations (A-Level only) questions

▶ Try answering this question with AI marking (free) →