Proteases and lipases are both enzymes involved in digestion. Explain why a protease enzyme cannot break down a lipid molecule, and describe what happens when a protease is used to digest a protein at its optimum temperature.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (5 marks)
Proteases have an active site that is shaped to fit only peptide bonds in proteins – the lock and key hypothesis shows that the enzyme’s active site is complementary to the substrate.
A lipid molecule is a long hydrocarbon chain with a polar head; it does not fit into the protease active site, so the enzyme cannot recognise or cleave it.
When a protease acts on a protein at its optimum temperature, the protein enters the active site forming an enzyme‑substrate complex. The enzyme catalyses the hydrolysis of peptide bonds, breaking the protein into amino acids. The products are released and the protease is unchanged and can bind another protein molecule.
A lipid molecule is a long hydrocarbon chain with a polar head; it does not fit into the protease active site, so the enzyme cannot recognise or cleave it.
When a protease acts on a protein at its optimum temperature, the protein enters the active site forming an enzyme‑substrate complex. The enzyme catalyses the hydrolysis of peptide bonds, breaking the protein into amino acids. The products are released and the protease is unchanged and can bind another protein molecule.
Examiner tips
- Use the lock‑and‑key language to explain specificity
- Show the enzyme‑substrate complex and the release of products
- Mention that the enzyme is unchanged and reusable
- Include the optimum temperature condition
Common mistakes
- Confusing lipase with protease activity
- Claiming the enzyme can act on lipids
- Omitting the enzyme‑substrate complex step
Mark scheme (5 marks)
- Each enzyme has an active site with a specific/complementary shape
- The lipid molecule does not have a complementary shape to the protease active site / is not the correct/matching substrate
- Reference to the lock and key hypothesis to explain enzyme specificity
- The protein substrate enters the active site of the protease, forming an enzyme-substrate complex
- The protein is broken down into amino acids / products are released and the enzyme is unchanged and can be reused
Related
- All WJEC A-Level Biology (Wales) revision notes →
- How to answer a "Explain and Describe" question →
- Decode the mark scheme abbreviations →
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