Outline how the functional groups present in ethanoic acid and ethylamine allow each compound to be classified as belonging to a homologous series, and identify one chemical property that distinguishes them from each other.

IB DP Chemistry Standard Level (2023 syllabus) — S3.2 Functional groups: classification of organic compounds · Outline · 4 marks · View as Markdown

Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).

Model answer (4 marks)

Ethanoic acid contains a carboxyl (–COOH) functional group, so it is a carboxylic acid and belongs to the carboxylic‑acid homologous series.
Ethylamine contains an amino (–NH₂) functional group, so it is an amine and belongs to the amine homologous series.
The carboxyl group makes ethanoic acid acidic – it donates a proton (H⁺). The amino group makes ethylamine basic – it accepts a proton (H⁺).
Thus the two compounds differ in acidity/basicity: ethanoic acid is acidic, ethylamine is basic, and they can react to form the salt ethylammonium ethanoate.

Examiner tips

  • Use the exact functional‑group names (carboxyl, amino). Mention the homologous series (carboxylic acid, amine). State the acid/base property clearly. Keep the answer short and to the point.

Common mistakes

  • Calling ethanoic acid a ‘carboxylate’ instead of a carboxylic acid. Mixing up the acid/base behaviour (e.g. saying ethylamine is acidic). Adding unnecessary detail such as reaction mechanisms beyond the salt formation.

Mark scheme (4 marks)

  1. Ethanoic acid contains a carboxyl (–COOH) functional group, which classifies it as a carboxylic acid.
  2. Ethylamine contains an amino (–NH₂) functional group, which classifies it as an amine.
  3. Ethanoic acid is acidic / donates a proton (H⁺), whereas ethylamine is basic / accepts a proton (H⁺).
  4. Ethanoic acid reacts with ethylamine (or other bases/carbonates) but ethylamine does not react in the same way / they react together to form a salt (ethylammonium ethanoate).

Key terms in this question

functional group · homologous series

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