Methane is the simplest alkane. Describe what happens when methane reacts with chlorine in the presence of ultraviolet light, and explain why this type of reaction is described as substitution.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
Ultraviolet light is required to initiate the reaction by breaking the C–H bond in methane, forming a methyl radical and a hydrogen chloride radical. The methyl radical then reacts with a chlorine molecule, replacing one hydrogen atom with a chlorine atom. The product is chloromethane (CH₃Cl). This reaction is called a substitution because a hydrogen atom is replaced by a chlorine atom rather than a new group being added across a bond.
Examiner tips
- Mention UV light as the initiator, the formation of radicals, and the replacement of H by Cl
- State the product CH₃Cl explicitly
- Explain substitution as replacement of an atom/group
Common mistakes
- Saying the reaction is an addition rather than a substitution
- Omitting the role of UV light or radicals
- Failing to name the product CH₃Cl
Mark scheme (4 marks)
- Ultraviolet light is needed to initiate / start the reaction
- A hydrogen atom in methane is replaced by a chlorine atom
- Chloromethane (CH3Cl) is formed as an organic product
- Substitution means an atom (or group) is replaced by another atom (or group), so a hydrogen atom is replaced rather than an addition across a bond occurring
Key terms in this question
alkane · substitution · ultraviolet light
Related
- All Cambridge International IGCSE Chemistry (0620) revision notes →
- How to answer a "Describe and Explain" question →
- Decode the mark scheme abbreviations →
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