Huntington's disease is a genetic disorder caused by a dominant gene mutation. Explain why a child can develop Huntington's disease even if only one parent carries the mutant allele, and describe how this pattern of inheritance differs from that of a recessive genetic disorder such as cystic fibrosis.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Huntington's disease is a late-onset neurological condition affecting muscle control and cognition. It is caused by a dominant allele on an autosome. Cystic fibrosis is caused by a recessive allele on an autosome.
Model answer (5 marks)
A dominant allele means only one copy is required for the phenotype to appear. If one parent is heterozygous (M/m) for the Huntington’s allele, each gamete has a 50 % chance of carrying the mutant allele, so a child has a 1 in 2 chance of inheriting it and developing the disease.
In contrast, cystic fibrosis is recessive. A child must inherit two mutant alleles (m/m) to show symptoms. A single mutant allele (m) results in a carrier (m/M) who is phenotypically normal. Thus two carrier parents can produce an affected child with a 25 % (1 in 4) probability.
Therefore, Huntington’s disease can arise from a single affected parent, whereas cystic fibrosis requires both parents to be carriers for an affected child to be possible.
In contrast, cystic fibrosis is recessive. A child must inherit two mutant alleles (m/m) to show symptoms. A single mutant allele (m) results in a carrier (m/M) who is phenotypically normal. Thus two carrier parents can produce an affected child with a 25 % (1 in 4) probability.
Therefore, Huntington’s disease can arise from a single affected parent, whereas cystic fibrosis requires both parents to be carriers for an affected child to be possible.
Examiner tips
- Mention the 50% transmission for a dominant allele; state the 25% risk for two carrier parents; use terms ‘heterozygous’, ‘carrier’, ‘recessive’ and ‘dominant’ exactly as in the mark scheme.
- Show the difference in required allele copies clearly: one for dominant, two for recessive.
Common mistakes
- Confusing the probability of transmission (using 1/4 instead of 1/2 for Huntington’s); Failing to explain that a single mutant allele is enough for the dominant disorder; Mixing up carrier status with affected status for cystic fibrosis.
Mark scheme (5 marks)
- The Huntington's disease allele is dominant, so only one copy of the mutant allele is needed for the disorder to be expressed.
- If one parent is heterozygous for the dominant allele, there is a 50% (1 in 2) chance of passing the mutant allele to each child.
- In cystic fibrosis, the allele is recessive, so a child must inherit two copies of the mutant allele (one from each parent) to develop the disorder.
- A person who inherits only one copy of the recessive cystic fibrosis allele is a carrier and does not show symptoms of the disorder.
- Therefore, unlike Huntington's disease, cystic fibrosis can be passed on by two unaffected carrier parents, and the probability of an affected child is 25% (1 in 4) when both parents are carriers.
Key terms in this question
gene mutation · genetic disorder
Related
- All Pearson Edexcel A-Level Biology A (9BI0) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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