Explain why the tertiary structure of an enzyme is essential for its function, referring to the role of bonds that maintain this structure.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Enzymes are globular proteins whose function depends on the precise three-dimensional shape of their active site. This shape is determined by the tertiary structure of the polypeptide chain.
Model answer (4 marks)
The tertiary structure gives the enzyme a specific three‑dimensional shape, creating an active site that is complementary to the substrate.
The shape is maintained by non‑covalent bonds – hydrogen bonds, ionic bonds, hydrophobic interactions – and covalent disulfide bonds.
If these bonds are broken (for example by heat or a change in pH) the protein unfolds (denatures) and the active site loses its shape.
Without a complementary active site the enzyme cannot bind the substrate, so enzyme‑substrate complexes cannot form and catalysis does not occur.
The shape is maintained by non‑covalent bonds – hydrogen bonds, ionic bonds, hydrophobic interactions – and covalent disulfide bonds.
If these bonds are broken (for example by heat or a change in pH) the protein unfolds (denatures) and the active site loses its shape.
Without a complementary active site the enzyme cannot bind the substrate, so enzyme‑substrate complexes cannot form and catalysis does not occur.
Examiner tips
- Mention the active site’s complementarity first, then list at least one bond type, explain denaturation, and link loss of shape to loss of catalysis.
- Use the word "tertiary structure" and specific bond names; keep the answer concise and structured.
Common mistakes
- Failing to name a bond type that stabilises tertiary structure.
- Not linking denaturation to loss of active‑site shape and therefore loss of catalysis.
Mark scheme (4 marks)
- The tertiary structure creates a specifically shaped active site that is complementary to the substrate
- Named bond(s) that maintain tertiary structure — at least one of: hydrogen bonds, disulfide bonds, ionic bonds, hydrophobic interactions
- If these bonds are disrupted (e.g. by heat or pH change) the tertiary structure is altered / lost (denaturation)
- Altered tertiary structure means the active site is no longer complementary to the substrate, so enzyme–substrate complexes cannot form and catalysis cannot occur
Key terms in this question
Related
- All OCR A-Level Biology A (H420) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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