Explain why the lattice enthalpy of magnesium oxide (MgO) is much greater in magnitude than the lattice enthalpy of sodium chloride (NaCl), using Coulomb's law to support your answer.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Lattice enthalpy is a key quantity used in Born–Haber cycles to assess the stability of ionic compounds. The lattice enthalpy of MgO is approximately −3791 kJ mol⁻¹, whilst that of NaCl is approximately −787 kJ mol⁻¹.
Model answer (4 marks)
The lattice enthalpy is proportional to the product of the charges of the ions and inversely proportional to the inter‑ionic distance (Coulomb’s law: ΔH_latt∝q_+q_−/r). In MgO the ions are Mg²⁺ and O²⁻, giving a charge product of 2×2=4. In NaCl the ions are Na⁺ and Cl⁻, giving a charge product of 1×1=1. Thus the electrostatic attraction in MgO is four times stronger. Additionally, Mg²⁺ and O²⁻ are smaller than Na⁺ and Cl⁻, so the inter‑ionic distance r in MgO is shorter. The combination of a larger charge product and a smaller r makes the electrostatic attraction in MgO much stronger, resulting in a lattice enthalpy of about –3791 kJ mol⁻¹ versus –787 kJ mol⁻¹ for NaCl.
Examiner tips
- Use Coulomb’s law explicitly (q₁q₂/r) to link charge and distance to lattice enthalpy.
- State the charge products (4 vs 1) and the relative ion sizes clearly.
- Explain that a larger charge product and shorter distance give a more negative lattice enthalpy.
Common mistakes
- Confusing lattice enthalpy sign (more negative means stronger attraction).
- Omitting the ion size argument or the charge product comparison.
Mark scheme (4 marks)
- Lattice enthalpy depends on the charges of the ions and the distance between them (Coulomb's law / electrostatic attraction).
- Mg²⁺ and O²⁻ each carry a charge of 2+ and 2− respectively, giving a charge product of 4, compared with Na⁺ (1+) and Cl⁻ (1−) with a charge product of 1.
- Mg²⁺ and O²⁻ are smaller ions than Na⁺ and Cl⁻ respectively, so the interionic distance in MgO is shorter.
- Both the higher charge and the shorter interionic distance result in a much stronger electrostatic attraction in MgO, giving it a significantly larger (more negative) lattice enthalpy than NaCl.
Key terms in this question
lattice enthalpy · Coulomb's law
Related
- All IB DP Chemistry Standard Level (2023 syllabus) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
More Energy cycles in reactions questions
- Explain why the electron affinity of chlorine is exothermic whilst the second el…
- Using the concept of an enthalpy cycle, explain why the standard enthalpy of for…
- Explain why the first ionisation energy of sodium is endothermic and why it is m…
- Explain why the standard enthalpy of atomisation of a metal is always a positive…