Explain why the fundamental frequency of a standing wave on a stretched string increases when the tension in the string is increased, whilst the length of the string remains constant.

IB DP Physics Higher Level (2023 syllabus) — C.4 Standing waves and resonance · Explain · 4 marks · View as Markdown

Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).

Model answer (4 marks)

The wave speed on a stretched string is v=√(T/μ). When the tension T is increased, v increases.
For a string fixed at both ends the fundamental mode must have nodes at the ends, so its wavelength is λ=2L, which is fixed because L is constant.
Frequency is f=v/λ. With λ unchanged, the increase in v gives a proportional increase in f.
Thus f∝√T, so the fundamental frequency rises when the tension is increased.

Examiner tips

  • Show the wave‑speed equation and explain the dependence on tension.
  • State that λ=2L for the fundamental and that L is constant.
  • Use f=v/λ to link the increase in v to an increase in f.
  • Mention the proportionality f∝√T for clarity.

Common mistakes

  • Confusing the fundamental wavelength with higher harmonics.
  • Forgetting that λ remains 2L when tension changes.
  • Using the wrong wave‑speed formula (e.g. v=√(T/ρ) instead of μ).

Mark scheme (4 marks)

  1. The wave speed on a stretched string increases when tension increases
  2. For a string fixed at both ends, the boundary conditions require nodes at each end, fixing the wavelength of the fundamental mode at twice the string length
  3. Since frequency equals wave speed divided by wavelength (f = v/λ), and wavelength is unchanged, the increase in wave speed produces a proportional increase in frequency
  4. Quantitative reasoning: wave speed v = √(T/μ), so v ∝ √T, meaning the fundamental frequency f ∝ √T and increases with tension

Key terms in this question

fundamental frequency · standing wave · tension

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