Explain why the current through a metallic conductor is directly proportional to the potential difference applied across it, using a microscopic model of charge carriers.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
A greater potential difference across a metallic conductor creates a larger electric field inside the conductor. The electric field exerts a force on the conduction electrons, increasing their mean drift velocity. Current is given by I = nAvq, where n is the number of charge carriers per unit volume, A the cross‑sectional area, v the mean drift velocity and q the charge of an electron. Thus, if the drift velocity increases in proportion to the applied potential difference, the current increases proportionally. At a constant temperature the collision frequency of the electrons – and therefore the resistance – remains unchanged, so the linear (Ohmic) relationship between current and potential difference is preserved.
Examiner tips
- Use the equation I = nAvq to link drift velocity to current
- Explain that the electric field is proportional to the applied potential difference
- Mention that resistance stays constant at fixed temperature to justify linearity
Common mistakes
- Confusing electric field with potential difference
- Failing to state that resistance is constant at constant temperature
- Using the wrong sign for electron charge or omitting the charge magnitude in the current formula
Mark scheme (4 marks)
- A greater potential difference produces a greater electric field within the conductor
- A greater electric field exerts a greater force on the conduction electrons, giving them a greater mean drift velocity
- Current is proportional to mean drift velocity (I = nAvq), so if drift velocity doubles when pd doubles, current doubles
- At constant temperature the frequency of collisions (and hence resistance) remains constant, preserving the linear/ohmic relationship
Key terms in this question
Related
- All IB DP Physics Higher Level (2023 syllabus) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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