Explain why denaturation of an enzyme results in loss of its catalytic activity.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
Denaturation breaks the non‑covalent bonds that maintain the enzyme’s tertiary structure, causing it to unfold. The altered three‑dimensional conformation changes the shape of the active site, so the substrate can no longer bind. Without substrate binding the enzyme–substrate complex cannot form and the enzyme cannot lower the activation energy, so catalytic activity is lost.
Examiner tips
- Show the chain: denaturation → loss of tertiary structure → altered active site → no substrate binding → no catalysis
- Use terms: hydrogen bonds, ionic bonds, hydrophobic interactions, tertiary structure, active site, induced fit
Common mistakes
- Confusing denaturation with irreversible inactivation; forgetting to mention loss of substrate binding
- Using vague phrases like ‘enzyme is damaged’ without linking to structure and activity
Mark scheme (4 marks)
- Denaturation disrupts non-covalent interactions (hydrogen bonds, ionic bonds, hydrophobic interactions) that maintain tertiary structure
- The three-dimensional (tertiary) structure / conformation of the enzyme is altered / unfolded
- The active site changes shape so substrate can no longer bind (induced fit / complementary shape is lost)
- Without substrate binding, the enzyme–substrate complex cannot form and so catalysis / lowering of activation energy does not occur
Key terms in this question
Related
- All IB DP Biology Higher Level (2023 syllabus) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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