Explain why carbon nanotubes exhibit exceptionally high tensile strength and are also able to conduct electricity along their length.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Carbon nanotubes (CNTs) are cylindrical allotropes of carbon in which the carbon atoms are arranged in a hexagonal lattice rolled into a seamless tube. They have tensile strengths far exceeding that of steel and can conduct electricity along their axis.
Model answer (4 marks)
Each carbon atom in a CNT is sp² hybridised, forming three σ bonds with neighbouring carbons in a trigonal‑planar arrangement that creates a continuous, rigid covalent network around the tube.
The σ bonds are strong, directional covalent bonds that require a large amount of energy to break, giving the CNT an exceptionally high tensile strength.
The remaining valence electron on each carbon occupies a p orbital perpendicular to the tube wall, producing a delocalised π system.
These delocalised π electrons can move freely along the tube axis, allowing electrical conduction along the length of the CNT.
The σ bonds are strong, directional covalent bonds that require a large amount of energy to break, giving the CNT an exceptionally high tensile strength.
The remaining valence electron on each carbon occupies a p orbital perpendicular to the tube wall, producing a delocalised π system.
These delocalised π electrons can move freely along the tube axis, allowing electrical conduction along the length of the CNT.
Examiner tips
- Use the word ‘sp² hybridised’ and ‘σ bonds’ to show understanding of bonding. Explain that σ bonds are strong and directional. Mention the delocalised π system and its role in conductivity. Keep the answer concise and directly linked to the marks scheme.
Common mistakes
- Confusing sp³ with sp² hybridisation. Forgetting to mention the delocalised π electrons. Using vague terms like ‘strong bonds’ without specifying σ bonds.
Mark scheme (4 marks)
- Each carbon atom forms three sigma (σ) bonds to neighbouring carbon atoms in a trigonal planar / sp² hybridised arrangement, creating a continuous, rigid covalent network along and around the tube.
- The strong, directional covalent bonds require large amounts of energy to break, accounting for the exceptionally high tensile strength.
- The fourth valence electron of each carbon atom is not involved in sigma bonding and occupies a p orbital perpendicular to the tube wall, forming a delocalised π system.
- These delocalised π electrons are mobile along the length of the tube and can carry charge, allowing electrical conduction along the nanotube axis.
Key terms in this question
carbon nanotube · tensile strength
Related
- All IB DP Chemistry Higher Level (2023 syllabus) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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