Explain why a dim source of light with a high enough frequency can release electrons from a metal surface, but a very bright source of light with a lower frequency cannot.

AQA A-Level Physics (7408) — 3.2.2 EM Radiation and Quantum Phenomena · Explain · 5 marks · View as Markdown

Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).

In the photoelectric effect, the emission of electrons from a metal surface depends on the properties of the light used.

Model answer (5 marks)

Light is quantised – it consists of photons.

The energy of each photon is given by E=hf, where h is Planck’s constant and f is the frequency of the light. The intensity (brightness) of the light only tells how many photons reach the surface per unit time; it does not change the energy of each photon.

For an electron to be emitted from a metal, a photon must supply at least the work function (ϕ) of that metal. If hf>ϕ, the electron can be released; if hf<ϕ, no electron can be ejected, no matter how many photons arrive.

Thus a dim source of high‑frequency light contains photons whose energy exceeds the work function, so electrons are emitted. A bright source of low‑frequency light contains photons whose energy is below the work function, so no electrons are emitted, even though the intensity is high.

Examiner tips

  • Mention photons and E=hf; link frequency to energy, not intensity; state work function condition; give example of high‑freq dim vs low‑freq bright.

Common mistakes

  • Confusing intensity with photon energy; writing that more photons mean more energy per electron; neglecting the work function requirement.

Mark scheme (5 marks)

  1. Light is made up of photons (discrete packets/quanta of energy)
  2. The energy of a photon depends on its frequency (not intensity)
  3. A single photon must have enough energy to overcome the work function of the metal in order to release an electron
  4. The high-frequency (dim) source has photons with enough energy to exceed the work function, so electrons are released
  5. The low-frequency (bright) source has photons with insufficient energy to overcome the work function, so no electrons are released regardless of intensity

Key terms in this question

frequency

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