Explain how the relative formula mass of magnesium hydroxide, Mg(OH)₂, is determined from the relative atomic masses of its constituent elements, and state the relative formula mass of Mg(OH)₂. (Relative atomic masses: H = 1, O = 16, Mg = 24)
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
The relative formula mass of Mg(OH)₂ is found by adding the relative atomic masses of all the atoms in the formula.
Mg(OH)₂ contains 1 Mg, 2 O and 2 H atoms.
Relative formula mass = 24 + (2 × 16) + (2 × 1) = 24 + 32 + 2 = 58.
Thus the relative formula mass of Mg(OH)₂ is 58.
Mg(OH)₂ contains 1 Mg, 2 O and 2 H atoms.
Relative formula mass = 24 + (2 × 16) + (2 × 1) = 24 + 32 + 2 = 58.
Thus the relative formula mass of Mg(OH)₂ is 58.
Examiner tips
- Show the full calculation with the multiplication for each element.
- Mention the number of each atom in the formula.
- Use the correct units (amu) implicitly by giving the numerical value.
- Keep the answer concise and to the point.
Common mistakes
- Omitting the multiplication step and writing only 24 + 32 + 2 without explanation.
- Using the wrong number of atoms (e.g., 1 O instead of 2).
- Confusing relative atomic mass with atomic weight or using incorrect values.
Mark scheme (4 marks)
- Relative formula mass is found by adding together the relative atomic masses of all atoms in the formula
- Correct identification that there are one Mg, two O, and two H atoms in Mg(OH)₂
- Correct working: 24 + (2 × 16) + (2 × 1) OR 24 + 32 + 2
- Relative formula mass of Mg(OH)₂ = 58
Key terms in this question
relative formula mass · relative atomic mass
Related
- All Cambridge International IGCSE Chemistry (0620) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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