Explain how the Bohr effect enables efficient delivery of oxygen to actively respiring tissues.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
Actively respiring tissues produce more CO₂, lowering local pH (increasing acidity). The lower pH raises H⁺ concentration, which reduces haemoglobin’s affinity for O₂. Consequently the O₂–haemoglobin dissociation curve shifts to the right, so at any given PO₂ more O₂ is unloaded. This ensures that tissues with the highest metabolic demand receive the most oxygen, matching supply to demand.
Examiner tips
- Use the phrase ‘shift to the right’ to show understanding of the curve.
- Explain the link between CO₂, pH and H⁺ concentration.
- Show that unloading occurs at the same PO₂ in tissues.
- Mention that this matches supply to demand.”]
Mark scheme (4 marks)
- Actively respiring tissues produce more carbon dioxide, lowering local pH (increasing acidity).
- Lower pH (higher H⁺ concentration) causes haemoglobin to have a reduced affinity for oxygen.
- The oxygen–haemoglobin dissociation curve shifts to the right, meaning more oxygen is unloaded at any given partial pressure of oxygen.
- This ensures that tissues with the highest metabolic demand receive the most oxygen, matching oxygen supply to demand.
Key terms in this question
Related
- All IB DP Biology Standard Level (2023 syllabus) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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