Chlorine, bromine and iodine are all halogens in Group 7 of the periodic table. Describe and explain the trend in reactivity of the halogens as you go down Group 7, and explain what happens when chlorine water is added to a solution of potassium bromide.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
Reactivity decreases down Group 7 because each successive halogen atom is larger and has a lower effective nuclear charge, making it harder to gain an electron and form the halide ion.
When chlorine water is added to a potassium bromide solution, chlorine displaces bromine from the bromide ion:
Cl₂ + 2 KBr → 2 KCl + Br₂
The solution turns orange‑brown as bromine is produced.
When chlorine water is added to a potassium bromide solution, chlorine displaces bromine from the bromide ion:
Cl₂ + 2 KBr → 2 KCl + Br₂
The solution turns orange‑brown as bromine is produced.
Examiner tips
- Use the word ‘decreases’ and explain size/effective nuclear charge. Show the displacement equation and the colour change. Link the displacement to the relative reactivity of the halogens.
Common mistakes
- Saying reactivity increases down the group. Forgetting that the reaction produces Br₂. Using the wrong equation (e.g. Cl₂ + Br⁻ → Cl⁻ + Br₂).
Mark scheme (4 marks)
- Reactivity decreases going down Group 7
- Each halogen atom gains one electron to form a halide ion, and atoms become larger down the group so gaining an electron becomes more difficult / less easy
- Chlorine displaces bromide ions from potassium bromide solution / a displacement reaction occurs
- The solution turns orange/brown (as bromine is produced)
Key terms in this question
Related
- All Pearson Edexcel International GCSE Chemistry (4CH1) revision notes →
- How to answer a "Describe and explain" question →
- Decode the mark scheme abbreviations →
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