Carboxylic acids can react with alcohols to form esters in a process called esterification. Pentyl methanoate is an ester that has a distinctive fruity smell. Describe how pentyl methanoate could be identified as an ester, and explain the conditions needed to produce it from its parent carboxylic acid and alcohol. Name the two reactants used.

Pentyl methanoate is an ester because it contains the ester functional group –COO–.

It can be identified as an ester by:
1. The presence of a carbonyl carbon bonded to an –O– group (C=O and C–O–C).
2. A characteristic fruity smell, typical of esters.
3. Infrared absorption at ~1735 cm⁻¹ (C=O stretch) and a weaker band at ~1250 cm⁻¹ (C–O stretch).

To produce it from its parent carboxylic acid and alcohol:
1. React methanoic acid (formic acid) with pentan‑1‑ol (pentanol).
2. Use a strong acid catalyst, e.g. concentrated H₂SO₄, to protonate the carbonyl oxygen.
3. Heat the mixture under reflux to drive off water and shift the equilibrium toward ester formation.

The two reactants are methanoic acid and pentan‑1‑ol.