Aqueous copper chloride solution is electrolysed using inert electrodes. Describe and explain what is produced at each electrode, naming the electrode in each case.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
At the anode (positive electrode) chloride ions are oxidised:
Cl⁻ → ½Cl₂(g) + e⁻
Chlorine gas is released. At the cathode (negative electrode) copper ions are reduced:
Cu²⁺ + 2e⁻ → Cu(s)
Copper metal is deposited on the cathode.
Cl⁻ → ½Cl₂(g) + e⁻
Chlorine gas is released. At the cathode (negative electrode) copper ions are reduced:
Cu²⁺ + 2e⁻ → Cu(s)
Copper metal is deposited on the cathode.
Examiner tips
- Use the correct electrode names (anode, cathode) and state the reaction direction (oxidation/reduction).
- Show the half‑reactions to justify why Cl₂ and Cu are produced.
- Mention that hydrogen evolution is suppressed because Cu²⁺ is reduced first.
Common mistakes
- Confusing anode with cathode or vice versa.
- Writing oxygen evolution at the anode instead of chlorine.
Mark scheme (4 marks)
- Chlorine is produced at the anode (positive electrode)
- At the anode, chloride ions lose electrons (oxidation), so chlorine is produced rather than oxygen because the solution contains halide ions
- Copper is produced at the cathode (negative electrode)
- At the cathode, copper ions gain electrons (reduction), so copper is deposited rather than hydrogen because copper is less reactive than hydrogen
Related
- All Edexcel GCSE Chemistry (1CH0) revision notes →
- How to answer a "Describe and explain" question →
- Decode the mark scheme abbreviations →
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