A student tests two solutions, X and Y, using Universal Indicator. Solution X gives a red colour and solution Y gives a purple colour. The student then adds an excess of sodium hydroxide solution to solution X and re-tests the resulting mixture with Universal Indicator, which now gives a green colour. Explain what these observations tell us about solutions X and Y, and explain what has happened chemically when sodium hydroxide was added to solution X.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
Solution X is acidic, giving a red colour with Universal Indicator.
Solution Y is alkaline, giving a purple colour.
Adding excess NaOH to X neutralises the acid:
acid + NaOH → salt + H₂O.
The green colour indicates the mixture is now neutral (pH≈7), showing that a salt and water have formed.
Solution Y is alkaline, giving a purple colour.
Adding excess NaOH to X neutralises the acid:
acid + NaOH → salt + H₂O.
The green colour indicates the mixture is now neutral (pH≈7), showing that a salt and water have formed.
Examiner tips
- Use the colour–pH chart to state X is acidic and Y is alkaline. Explain the neutralisation reaction and the change to green. Show the link between neutral pH and the green colour.
Common mistakes
- Confusing the colours (e.g., saying X is basic). Failing to mention the formation of a salt and water. Not linking the green colour to a neutral pH.
Mark scheme (4 marks)
- Solution X is acidic / is an acid
- Solution Y is alkaline / is a base / has a pH above 7
- The sodium hydroxide neutralised the acid in solution X
- The green colour shows the resulting mixture is neutral / has a pH of 7, so a salt and water were formed
Key terms in this question
Related
- All WJEC GCSE Chemistry (Wales) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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