A student submerges a small stone in a tank of seawater. The stone sinks to the bottom of the tank. Explain why the pressure acting on the stone increases as it sinks deeper into the seawater.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Seawater has a greater density than fresh water. The tank is open at the top.
Model answer (4 marks)
Pressure in a liquid increases with depth because the weight of the liquid column above the stone increases as it sinks.
The pressure at a depth h is given by p=ρgh, so a greater depth means a larger ρgh.
Seawater has a higher density than fresh water, so the same depth gives a higher pressure.
The pressure acts equally in all directions on the stone, so the upward buoyant force is balanced by the downward weight of the stone.
The pressure at a depth h is given by p=ρgh, so a greater depth means a larger ρgh.
Seawater has a higher density than fresh water, so the same depth gives a higher pressure.
The pressure acts equally in all directions on the stone, so the upward buoyant force is balanced by the downward weight of the stone.
Examiner tips
- Use the formula p=ρgh to show the depth dependence
- Mention the higher density of seawater
- Explain that pressure acts isotropically
- Keep the answer concise and use correct units
Common mistakes
- Confusing pressure with weight or buoyant force
- Using the wrong density (assuming fresh water)
- Forgetting that pressure acts in all directions
Mark scheme (4 marks)
- Pressure in a liquid increases with depth
- There is a greater weight / column of liquid above the stone at greater depth
- Pressure also depends on the density of the liquid
- Pressure acts equally in all directions at any point in the liquid
Key terms in this question
Related
- All Pearson Edexcel International GCSE Physics (4PH1) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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