A student investigates the effect of a competitive inhibitor on the rate of an enzyme-controlled reaction. The student finds that increasing the substrate concentration eventually restores the original maximum rate of reaction. Explain why increasing substrate concentration overcomes competitive inhibition.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
Competitive inhibitors have a structure similar to the substrate and bind to the active site of the enzyme. The binding is reversible, so the inhibitor can dissociate. When substrate concentration is increased, more substrate molecules are available to compete for the active site. At sufficiently high substrate concentrations, the probability that a substrate molecule occupies the active site is much greater than that of the inhibitor, so the enzyme is largely free to catalyse the reaction. Consequently the maximum rate (Vmax) is restored.
Examiner tips
- Use the term ‘competitive inhibitor’ and explain its reversible binding to the active site. Show that increasing [S] raises the likelihood of substrate outcompeting the inhibitor. Mention that Vmax is recovered when almost all sites are occupied by substrate.
- common_mistakes
- :
- Confusing competitive inhibition with non‑competitive inhibition. Forgetting to state that the inhibitor binds reversibly. Failing to explain that Vmax is restored because the inhibitor is displaced at high [S].
Mark scheme (4 marks)
- Competitive inhibitor has a similar shape to the substrate and binds to the active site
- Inhibitor binding is reversible / temporary
- At higher substrate concentrations, substrate molecules outcompete the inhibitor for the active site
- At very high substrate concentrations, virtually all active sites are occupied by substrate, so Vmax is restored
Key terms in this question
competitive inhibitor · substrate concentration · maximum rate of reaction
Related
- All OCR A-Level Biology A (H420) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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