A student dissolves 4.0 g of sodium hydroxide (NaOH) in water to make 500 cm³ of solution. Describe how the concentration of this solution would change if the student had instead dissolved the same 4.0 g of sodium hydroxide in only 250 cm³ of water. Explain why this change occurs.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Concentration is defined as the amount of substance in a certain volume of solution. The relative formula mass of NaOH is 40.
Model answer (4 marks)
The concentration would increase.
The concentration would double.
The same 4.0 g of NaOH (0.10 mol) is dissolved in a smaller volume.
There are twice as many moles of NaOH per dm³, so the concentration is twice as great.
The concentration would double.
The same 4.0 g of NaOH (0.10 mol) is dissolved in a smaller volume.
There are twice as many moles of NaOH per dm³, so the concentration is twice as great.
Examiner tips
- Use the word ‘increase’ or ‘be higher’ for the first point. State ‘double’ or ‘twice as great’ for the second. Mention the unchanged mass/moles of solute. Explain that moles per unit volume are higher.”]
- common_mistakes
- :
- Writing ‘decrease’ instead of ‘increase’. Forgetting to state that the mass of NaOH is unchanged. Using ‘half the concentration’ instead of ‘double’.”
Mark scheme (4 marks)
- The concentration would increase / be greater / be higher
- The concentration would double / be twice as great
- The same amount (mass/moles) of solute is dissolved in a smaller volume of solvent/solution
- There are more particles/moles of solute per dm³ (unit volume)
Key terms in this question
Related
- All AQA GCSE Chemistry (8462) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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