A student connects a 9 V battery to three identical lamps in series. Each lamp has a potential difference of 3 V across it and a current of 0.2 A flowing through it. Explain how energy is transferred in this circuit, starting from the battery and ending with what happens inside each lamp.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Model answer (4 marks)
Chemical energy stored in the 9 V battery is converted into electrical energy as the battery’s chemical reactions push electrons through the circuit.
The 9 V potential difference means each electron gains 9 J of energy as it moves from the negative to the positive terminal. In series, the 9 V is divided equally, so each lamp experiences a 3 V drop.
This 3 V drop represents the work done on each electron by the battery as it passes through the lamp’s filament; the current of 0.2 A carries 0.2 C s⁻¹, so the power delivered to each lamp is 3 V × 0.2 A = 0.6 W.
Inside the filament, the electrical energy is converted to thermal energy and light. Electrons collide with the metal ions, increasing the filament’s temperature and causing it to glow, while the rest of the energy is dissipated as heat.
Thus, chemical energy → electrical energy → work on charges → heat and light in the lamps.
The 9 V potential difference means each electron gains 9 J of energy as it moves from the negative to the positive terminal. In series, the 9 V is divided equally, so each lamp experiences a 3 V drop.
This 3 V drop represents the work done on each electron by the battery as it passes through the lamp’s filament; the current of 0.2 A carries 0.2 C s⁻¹, so the power delivered to each lamp is 3 V × 0.2 A = 0.6 W.
Inside the filament, the electrical energy is converted to thermal energy and light. Electrons collide with the metal ions, increasing the filament’s temperature and causing it to glow, while the rest of the energy is dissipated as heat.
Thus, chemical energy → electrical energy → work on charges → heat and light in the lamps.
Examiner tips
- Show the energy flow from battery to electrons, then to lamp; use the 9 V and 3 V values; mention current and power; explain heating via electron‑ion collisions.
Common mistakes
- Confusing chemical with electrical energy; not linking voltage to energy per charge; ignoring the role of electron collisions in heating; failing to state that light is also produced.
Mark scheme (4 marks)
- Chemical energy in the battery is transferred to electrical energy (in the circuit / to the charges)
- The potential difference (voltage) across each lamp shows the energy transferred per unit charge between those two points / the battery does work on the charges
- Electrical energy is transferred to thermal (heat) energy and light energy in each lamp / current does work against the resistance of the lamp
- This heating occurs because electrons collide with ions in the metal filament / the filament's temperature increases due to these collisions
Key terms in this question
Related
- All Pearson Edexcel International GCSE Physics (4PH1) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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