A student carries a heavy bag up a flight of stairs at a steady speed, then walks along a horizontal corridor at the same steady speed. State what happens to the rate at which the student does work against gravity as they move from the stairs to the corridor, and explain why.

Cambridge International IGCSE Physics (0625) — 1.7 Energy, work and power · Explain · 4 marks · View as Markdown

Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).

Model answer (4 marks)

The rate of doing work against gravity decreases to zero when the student moves onto the corridor.
1. On the stairs the student and bag gain height; the force of gravity acts downwards while the student moves upwards, so work is done against gravity.
2. On the corridor the motion is horizontal, so there is no change in height and the displacement is perpendicular to the gravitational force.
3. Work is only done when a force has a component in the direction of the displacement; here that component is zero.
4. Therefore the power (rate of doing work) against gravity falls to zero on the corridor.

Examiner tips

  • State the change in power first, then explain using force–displacement relationship.
  • Use the term ‘work against gravity’ and ‘no change in height’ to match the scheme.
  • Show the reasoning in two clear points: vertical motion vs horizontal motion.

Common mistakes

  • Confusing work with power or vice‑versa.
  • Saying the work remains the same instead of noting it drops to zero.
  • Ignoring that work is zero when displacement is perpendicular to the force.

Mark scheme (4 marks)

  1. The rate of doing work against gravity decreases (to zero) on the corridor
  2. On the corridor there is no change in height / the student moves horizontally
  3. Work is done (only) when a force moves an object in the direction of the force
  4. On the stairs, work is done against gravity because the student (and bag) gain height / move in the direction opposing the gravitational force

Key terms in this question

rate

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