A large cargo ship floats on the sea. The ship has a flat-bottomed hull with a total area in contact with the water of 4000 m². The same ship, when fully loaded with cargo, sinks deeper into the water. Explain why the fully loaded ship exerts a greater pressure on the water beneath its hull than the empty ship does.
Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).
Pressure is defined as the force per unit area acting on a surface. When an object rests on or in a fluid, it exerts a downward force equal to its weight over the area of contact.
Model answer (4 marks)
The loaded ship has a larger weight, so the downward force on the hull increases.
The hull’s contact area with the water stays essentially the same (4000 m²) or does not increase enough to offset the added weight.
Pressure is force divided by area. With a larger force and the same area, the pressure on the water increases.
Thus the fully loaded ship exerts a greater pressure on the water beneath its hull than the empty ship.
The hull’s contact area with the water stays essentially the same (4000 m²) or does not increase enough to offset the added weight.
Pressure is force divided by area. With a larger force and the same area, the pressure on the water increases.
Thus the fully loaded ship exerts a greater pressure on the water beneath its hull than the empty ship.
Examiner tips
- Use the definition of pressure (P=F/A) to link force and area.
- Show the weight increase first, then note the area is unchanged.
- Explain the consequence for pressure clearly.
Mark scheme (4 marks)
- Loading the ship increases its total weight (downward force)
- The area of the hull in contact with the water remains the same (or does not increase sufficiently to compensate)
- Pressure = force ÷ area, so greater force with the same area gives greater pressure
- Therefore the pressure on the water beneath the hull is greater for the loaded ship
Key terms in this question
Related
- All Cambridge International IGCSE Physics (0625) revision notes →
- How to answer a "Explain" question →
- Decode the mark scheme abbreviations →
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