A cyclist is travelling along a straight, flat road at a constant velocity of 12 m/s. The cyclist then brakes uniformly and comes to rest in 6 seconds. Explain what the velocity–time graph for the entire journey described would look like, and describe the motion of the cyclist during each phase.

Edexcel A-Level Physics (9PH0) — 2.1 Motion · Explain · 5 marks · View as Markdown

Written & reviewed by James Millett — Biology (Imperial College London), PGCE Science (University of Cambridge).

A cyclist travels at a constant velocity before applying the brakes and stopping.

Model answer (5 marks)

The graph consists of two straight‑line sections. From t=0 to t≈2.0 s the line is horizontal at 12 m s⁻¹, showing the cyclist moves with constant velocity. From t≈2.0 s to t=8.0 s the line slopes downwards to 0 m s⁻¹, a straight line with a negative gradient, indicating a constant (uniform) deceleration. The slope equals –2 m s⁻² (12 m s⁻¹ ÷ 6 s). During the first phase the net force on the cyclist is zero; during the second phase a constant braking force produces the uniform deceleration until the cyclist stops at t=8 s.

Examiner tips

  • Show the two straight‑line sections and label the horizontal part at 12 m s⁻¹; give the slope of the braking section as –2 m s⁻².
  • Explain the forces: zero during constant speed, constant braking force during deceleration.
  • Mention that the graph ends at zero velocity after 6 s of braking.

Mark scheme (5 marks)

  1. The first section of the graph is a horizontal straight line (at 12 m/s), indicating constant velocity.
  2. During the constant velocity phase, acceleration is zero (resultant force is zero).
  3. The second section of the graph is a straight line with a negative gradient (sloping downward from 12 m/s to 0 m/s).
  4. The straight negative gradient indicates uniform / constant deceleration (deceleration is uniform because the gradient is constant).
  5. The graph ends at zero velocity after 6 seconds of braking, showing the cyclist has come to rest / stopped.

Key terms in this question

constant velocity · velocity–time graph

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